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Print proper error message if Lua expression parse fails

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Ilari Liusvaara 2013-11-26 08:23:16 +02:00
parent 5ccdb1be8c
commit 75a0f641f4
1 changed files with 2 additions and 1 deletions
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src/lua/lua.cpp
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@ -113,7 +113,8 @@ namespace
#define TEMPORARY "LUAINTERP_INTERNAL_COMMAND_TEMPORARY" #define TEMPORARY "LUAINTERP_INTERNAL_COMMAND_TEMPORARY"
const char* eval_lua_lua = "loadstring(" TEMPORARY ")();"; const char* eval_lua_lua = "local fn = loadstring(" TEMPORARY "); if fn then fn(); else print("
"\"Parse error in Lua statement\"); end;";
const char* run_lua_lua = "dofile(" TEMPORARY ");"; const char* run_lua_lua = "dofile(" TEMPORARY ");";
void run_lua_fragment(lua_state& L) throw(std::bad_alloc) void run_lua_fragment(lua_state& L) throw(std::bad_alloc)